An elevator weighing 3.5 x 10-6 N is raised to a height of 1000 m in the absence of friction, the work done is_________________?

A. 3.5 x 10-3 J
B. 3.5 x 104 J
C. 3.5 x 106 J
D. 3.5 x 109 J

To find the work done in raising the elevator, we can use the formula for work done against gravity:

Work=Force×Distance

Given:

Force (FFF) = 3.5×10−63.5 times 10^{-6}3.5×10−6 N
Distance (ddd) = 1000 m

Substituting the given values:

Work=3.5×10−6N×1000m

Work=3.5×10−3J

If correct, the work done is 3.5×10−33.5 times 10^{-3}3.5×10−3 Joules.